Base | Representation |
---|---|
bin | 100110101100111101100110… |
… | …0000110010001110011101011 |
3 | 1122122100220020020000001121002 |
4 | 1031121323030012101303223 |
5 | 324110110414213412134 |
6 | 3204011522021305215 |
7 | 131464223363302613 |
oct | 11531731406216353 |
9 | 1578326206001532 |
10 | 340431122013419 |
11 | 995210343a0238 |
12 | 322219b9b6520b |
13 | 117c5694c90368 |
14 | 600cd5054ba43 |
15 | 29555dc33187e |
hex | 1359ecc191ceb |
340431122013419 has 2 divisors, whose sum is σ = 340431122013420. Its totient is φ = 340431122013418.
The previous prime is 340431122013397. The next prime is 340431122013457. The reversal of 340431122013419 is 914310221134043.
It is an a-pointer prime, because the next prime (340431122013457) can be obtained adding 340431122013419 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-340431122013419 is a prime.
It is a super-3 number, since 3×3404311220134193 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (340431122012419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170215561006709 + 170215561006710.
It is an arithmetic number, because the mean of its divisors is an integer number (170215561006710).
Almost surely, 2340431122013419 is an apocalyptic number.
340431122013419 is a deficient number, since it is larger than the sum of its proper divisors (1).
340431122013419 is an equidigital number, since it uses as much as digits as its factorization.
340431122013419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 340431122013419 in words is "three hundred forty trillion, four hundred thirty-one billion, one hundred twenty-two million, thirteen thousand, four hundred nineteen".
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