Base | Representation |
---|---|
bin | 100110101101000011010010… |
… | …0011110010100111110100111 |
3 | 1122122102001202212022100122122 |
4 | 1031122012210132110332213 |
5 | 324110310431041143421 |
6 | 3204021302353020155 |
7 | 131465135246503112 |
oct | 11532064436247647 |
9 | 1578361685270578 |
10 | 340443342131111 |
11 | 9952623532555a |
12 | 3222424a55465b |
13 | 117c689190402b |
14 | 600d78d4a7579 |
15 | 2955aa50822ab |
hex | 135a1a4794fa7 |
340443342131111 has 2 divisors, whose sum is σ = 340443342131112. Its totient is φ = 340443342131110.
The previous prime is 340443342131107. The next prime is 340443342131119. The reversal of 340443342131111 is 111131243344043.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 340443342131111 - 22 = 340443342131107 is a prime.
It is a super-2 number, since 2×3404433421311112 (a number of 30 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340443342131119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170221671065555 + 170221671065556.
It is an arithmetic number, because the mean of its divisors is an integer number (170221671065556).
Almost surely, 2340443342131111 is an apocalyptic number.
340443342131111 is a deficient number, since it is larger than the sum of its proper divisors (1).
340443342131111 is an equidigital number, since it uses as much as digits as its factorization.
340443342131111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 340443342131111 its reverse (111131243344043), we get a palindrome (451574585475154).
The spelling of 340443342131111 in words is "three hundred forty trillion, four hundred forty-three billion, three hundred forty-two million, one hundred thirty-one thousand, one hundred eleven".
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