Base | Representation |
---|---|
bin | 1100101011110100… |
… | …1010011011001101 |
3 | 22210022011111120121 |
4 | 3022331022123031 |
5 | 23433141443432 |
6 | 1321513344541 |
7 | 150244200265 |
oct | 31275123315 |
9 | 8708144517 |
10 | 3405031117 |
11 | 1498062304 |
12 | 7b0408151 |
13 | 423597b17 |
14 | 24431a7a5 |
15 | 14dded197 |
hex | caf4a6cd |
3405031117 has 2 divisors, whose sum is σ = 3405031118. Its totient is φ = 3405031116.
The previous prime is 3405031039. The next prime is 3405031151. The reversal of 3405031117 is 7111305043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2218504201 + 1186526916 = 47101^2 + 34446^2 .
It is an emirp because it is prime and its reverse (7111305043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3405031117 - 219 = 3404506829 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3405031091 and 3405031100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3405041117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1702515558 + 1702515559.
It is an arithmetic number, because the mean of its divisors is an integer number (1702515559).
Almost surely, 23405031117 is an apocalyptic number.
It is an amenable number.
3405031117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3405031117 is an equidigital number, since it uses as much as digits as its factorization.
3405031117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 25.
The square root of 3405031117 is about 58352.6444730657. The cubic root of 3405031117 is about 1504.4359231627.
The spelling of 3405031117 in words is "three billion, four hundred five million, thirty-one thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •