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34102548497 is a prime number
BaseRepresentation
bin11111110000101010…
…111001100000010001
310021000122221221220202
4133300222321200101
51024320223022442
623355543544545
72315043610433
oct376052714021
9107018857822
1034102548497
111350aaaa486
126738a5b155
1332a63102a4
141917254653
15d48da8c32
hex7f0ab9811

34102548497 has 2 divisors, whose sum is σ = 34102548498. Its totient is φ = 34102548496.

The previous prime is 34102548461. The next prime is 34102548499. The reversal of 34102548497 is 79484520143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26694331456 + 7408217041 = 163384^2 + 86071^2 .

It is a cyclic number.

It is not a de Polignac number, because 34102548497 - 26 = 34102548433 is a prime.

Together with 34102548499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (34102548499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17051274248 + 17051274249.

It is an arithmetic number, because the mean of its divisors is an integer number (17051274249).

Almost surely, 234102548497 is an apocalyptic number.

It is an amenable number.

34102548497 is a deficient number, since it is larger than the sum of its proper divisors (1).

34102548497 is an equidigital number, since it uses as much as digits as its factorization.

34102548497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 967680, while the sum is 47.

The spelling of 34102548497 in words is "thirty-four billion, one hundred two million, five hundred forty-eight thousand, four hundred ninety-seven".