Base | Representation |
---|---|
bin | 110001101000111101111… |
… | …100001001110101000101 |
3 | 110002010000101220222221221 |
4 | 301220331330021311011 |
5 | 421342211230241401 |
6 | 11131034204440341 |
7 | 501311533612114 |
oct | 61507574116505 |
9 | 13063011828857 |
10 | 3411243212101 |
11 | 10a57779537aa |
12 | 4711565490b1 |
13 | 1b98a959c76a |
14 | bb168399c7b |
15 | 5db0321e7a1 |
hex | 31a3df09d45 |
3411243212101 has 2 divisors, whose sum is σ = 3411243212102. Its totient is φ = 3411243212100.
The previous prime is 3411243212063. The next prime is 3411243212119. The reversal of 3411243212101 is 1012123421143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3400520402500 + 10722809601 = 1844050^2 + 103551^2 .
It is a cyclic number.
It is not a de Polignac number, because 3411243212101 - 213 = 3411243203909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3411243219101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1705621606050 + 1705621606051.
It is an arithmetic number, because the mean of its divisors is an integer number (1705621606051).
Almost surely, 23411243212101 is an apocalyptic number.
It is an amenable number.
3411243212101 is a deficient number, since it is larger than the sum of its proper divisors (1).
3411243212101 is an equidigital number, since it uses as much as digits as its factorization.
3411243212101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 3411243212101 its reverse (1012123421143), we get a palindrome (4423366633244).
It can be divided in two parts, 341124 and 3212101, that added together give a square (3553225 = 18852).
The spelling of 3411243212101 in words is "three trillion, four hundred eleven billion, two hundred forty-three million, two hundred twelve thousand, one hundred one".
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