Base | Representation |
---|---|
bin | 1001111011011010000… |
… | …11011000111010011101 |
3 | 1012121112002002012200022 |
4 | 10331231003120322131 |
5 | 21042114244141110 |
6 | 420414111041525 |
7 | 33434366224160 |
oct | 4755503307235 |
9 | 1177462065608 |
10 | 341132021405 |
11 | 12174515081a |
12 | 561445102a5 |
13 | 26226593c06 |
14 | 12721bc5ad7 |
15 | 8d18754755 |
hex | 4f6d0d8e9d |
341132021405 has 128 divisors (see below), whose sum is σ = 508779823104. Its totient is φ = 214638796800.
The previous prime is 341132021341. The next prime is 341132021413. The reversal of 341132021405 is 504120231143.
It is a happy number.
It is not a de Polignac number, because 341132021405 - 26 = 341132021341 is a prime.
It is a super-2 number, since 2×3411320214052 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 349162277 + ... + 349163253.
It is an arithmetic number, because the mean of its divisors is an integer number (3974842368).
Almost surely, 2341132021405 is an apocalyptic number.
341132021405 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
341132021405 is a deficient number, since it is larger than the sum of its proper divisors (167647801699).
341132021405 is a wasteful number, since it uses less digits than its factorization.
341132021405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1275.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 341132021405 its reverse (504120231143), we get a palindrome (845252252548).
The spelling of 341132021405 in words is "three hundred forty-one billion, one hundred thirty-two million, twenty-one thousand, four hundred five".
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