341213250216143 has 2 divisors, whose sum is σ = 341213250216144. Its totient is φ = 341213250216142.

The previous prime is 341213250216131. The next prime is 341213250216191. The reversal of 341213250216143 is 341612052312143.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-341213250216143 is a prime.

It is a super-2 number, since 2×341213250216143² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 341213250216097 and 341213250216106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (341213250216193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170606625108071 + 170606625108072.

It is an arithmetic number, because the mean of its divisors is an integer number (170606625108072).

Almost surely, 2^{341213250216143} is an apocalyptic number.

341213250216143 is a deficient number, since it is larger than the sum of its proper divisors (1).

341213250216143 is an equidigital number, since it uses as much as digits as its factorization.

341213250216143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 341213250216143 in words is "three hundred forty-one trillion, two hundred thirteen billion, two hundred fifty million, two hundred sixteen thousand, one hundred forty-three".