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3412414303 is a prime number
BaseRepresentation
bin1100101101100101…
…0100111101011111
322210211001121101221
43023121110331133
523442034224203
61322335514211
7150364020514
oct31331247537
98724047357
103412414303
1114a1245411
127b2988967
13424c8157c
142452bd30b
1514e8aaabd
hexcb654f5f

3412414303 has 2 divisors, whose sum is σ = 3412414304. Its totient is φ = 3412414302.

The previous prime is 3412414259. The next prime is 3412414331. The reversal of 3412414303 is 3034142143.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3412414303 - 213 = 3412406111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3412414333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706207151 + 1706207152.

It is an arithmetic number, because the mean of its divisors is an integer number (1706207152).

Almost surely, 23412414303 is an apocalyptic number.

3412414303 is a deficient number, since it is larger than the sum of its proper divisors (1).

3412414303 is an equidigital number, since it uses as much as digits as its factorization.

3412414303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 3412414303 is about 58415.8737245280. The cubic root of 3412414303 is about 1505.5225027275.

Adding to 3412414303 its reverse (3034142143), we get a palindrome (6446556446).

The spelling of 3412414303 in words is "three billion, four hundred twelve million, four hundred fourteen thousand, three hundred three".