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3413111320110 = 235113770377337
BaseRepresentation
bin110001101010101101010…
…010011010111000101110
3110002021211121002201101110
4301222231102122320232
5421410022444220420
611131543420452450
7501406036353132
oct61525522327056
913067747081343
103413111320110
1110a65463a6a18
124715980aa126
131b9b1661810b
14bb2a45213c2
155dbb222cee0
hex31aad49ae2e

3413111320110 has 16 divisors (see below), whose sum is σ = 8191467168336. Its totient is φ = 910163018688.

The previous prime is 3413111320097. The next prime is 3413111320111. The reversal of 3413111320110 is 110231113143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3413111320111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56885188639 + ... + 56885188698.

It is an arithmetic number, because the mean of its divisors is an integer number (511966698021).

Almost surely, 23413111320110 is an apocalyptic number.

3413111320110 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

3413111320110 is an abundant number, since it is smaller than the sum of its proper divisors (4778355848226).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3413111320110 is a wasteful number, since it uses less digits than its factorization.

3413111320110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113770377347.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 3413111320110 its reverse (110231113143), we get a palindrome (3523342433253).

The spelling of 3413111320110 in words is "three trillion, four hundred thirteen billion, one hundred eleven million, three hundred twenty thousand, one hundred ten".

Divisors: 1 2 3 5 6 10 15 30 113770377337 227540754674 341311132011 568851886685 682622264022 1137703773370 1706555660055 3413111320110