Base | Representation |
---|---|
bin | 11111110010011001… |
… | …000000100000011111 |
3 | 10021002200021102121021 |
4 | 133302121000200133 |
5 | 1024400120204043 |
6 | 23402454345011 |
7 | 2315544136531 |
oct | 376231004037 |
9 | 107080242537 |
10 | 34131413023 |
11 | 13525324864 |
12 | 674665b167 |
13 | 32ac2a84a6 |
14 | 191b009851 |
15 | d4b6ab3ed |
hex | 7f264081f |
34131413023 has 2 divisors, whose sum is σ = 34131413024. Its totient is φ = 34131413022.
The previous prime is 34131413011. The next prime is 34131413027. The reversal of 34131413023 is 32031413143.
It is a strong prime.
It is an emirp because it is prime and its reverse (32031413143) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34131413023 is a prime.
It is a super-2 number, since 2×341314130232 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34131413027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17065706511 + 17065706512.
It is an arithmetic number, because the mean of its divisors is an integer number (17065706512).
Almost surely, 234131413023 is an apocalyptic number.
34131413023 is a deficient number, since it is larger than the sum of its proper divisors (1).
34131413023 is an equidigital number, since it uses as much as digits as its factorization.
34131413023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 34131413023 its reverse (32031413143), we get a palindrome (66162826166).
The spelling of 34131413023 in words is "thirty-four billion, one hundred thirty-one million, four hundred thirteen thousand, twenty-three".
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