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3413433152237 is a prime number
BaseRepresentation
bin110001101011000000011…
…110000111001011101101
3110002022200000200111001212
4301223000132013023231
5421411202341332422
611132035354444205
7501420025032203
oct61530036071355
913068600614055
103413433152237
1110a66a1032189
12471667a33665
131b9b681bb224
14bb2d5179073
155dbd06009e2
hex31ac07872ed

3413433152237 has 2 divisors, whose sum is σ = 3413433152238. Its totient is φ = 3413433152236.

The previous prime is 3413433152221. The next prime is 3413433152243. The reversal of 3413433152237 is 7322513343143.

3413433152237 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2336049355396 + 1077383796841 = 1528414^2 + 1037971^2 .

It is a cyclic number.

It is not a de Polignac number, because 3413433152237 - 24 = 3413433152221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3413433152194 and 3413433152203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3413433152737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706716576118 + 1706716576119.

It is an arithmetic number, because the mean of its divisors is an integer number (1706716576119).

Almost surely, 23413433152237 is an apocalyptic number.

It is an amenable number.

3413433152237 is a deficient number, since it is larger than the sum of its proper divisors (1).

3413433152237 is an equidigital number, since it uses as much as digits as its factorization.

3413433152237 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 544320, while the sum is 41.

The spelling of 3413433152237 in words is "three trillion, four hundred thirteen billion, four hundred thirty-three million, one hundred fifty-two thousand, two hundred thirty-seven".