Base | Representation |
---|---|
bin | 100110110100000010101100… |
… | …0100011111010001010101111 |
3 | 1122202210220202121021011010222 |
4 | 1031220011120203322022233 |
5 | 324222031140121400142 |
6 | 3210034521451321555 |
7 | 131624430612026312 |
oct | 11550053043721257 |
9 | 1582726677234128 |
10 | 341404141200047 |
11 | 99866757357762 |
12 | 3235a4b01502bb |
13 | 11866370535473 |
14 | 6044097508979 |
15 | 2970a8a052bd2 |
hex | 13681588fa2af |
341404141200047 has 2 divisors, whose sum is σ = 341404141200048. Its totient is φ = 341404141200046.
The previous prime is 341404141200029. The next prime is 341404141200049. The reversal of 341404141200047 is 740002141404143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 341404141200047 - 212 = 341404141195951 is a prime.
Together with 341404141200049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (341404141200049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170702070600023 + 170702070600024.
It is an arithmetic number, because the mean of its divisors is an integer number (170702070600024).
Almost surely, 2341404141200047 is an apocalyptic number.
341404141200047 is a deficient number, since it is larger than the sum of its proper divisors (1).
341404141200047 is an equidigital number, since it uses as much as digits as its factorization.
341404141200047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 35.
The spelling of 341404141200047 in words is "three hundred forty-one trillion, four hundred four billion, one hundred forty-one million, two hundred thousand, forty-seven".
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