Base | Representation |
---|---|
bin | 110001101011100100111… |
… | …000110100001100101111 |
3 | 110002101020121100110221021 |
4 | 301223210320310030233 |
5 | 421413430244212033 |
6 | 11132220142115011 |
7 | 501441124211551 |
oct | 61534470641457 |
9 | 13071217313837 |
10 | 3414044132143 |
11 | 10a69849aa457 |
12 | 4717b857ba67 |
13 | 1b9c3495c6b8 |
14 | bb35237d4d1 |
15 | 5dc1908bb2d |
hex | 31ae4e3432f |
3414044132143 has 2 divisors, whose sum is σ = 3414044132144. Its totient is φ = 3414044132142.
The previous prime is 3414044132119. The next prime is 3414044132153. The reversal of 3414044132143 is 3412314404143.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3414044132143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3414044132099 and 3414044132108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3414044132153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707022066071 + 1707022066072.
It is an arithmetic number, because the mean of its divisors is an integer number (1707022066072).
Almost surely, 23414044132143 is an apocalyptic number.
3414044132143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3414044132143 is an equidigital number, since it uses as much as digits as its factorization.
3414044132143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 3414044132143 its reverse (3412314404143), we get a palindrome (6826358536286).
The spelling of 3414044132143 in words is "three trillion, four hundred fourteen billion, forty-four million, one hundred thirty-two thousand, one hundred forty-three".
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