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34141304401 is a prime number
BaseRepresentation
bin11111110010111110…
…101111011001010001
310021010100212222000121
4133302332233121101
51024410133220101
623403450350241
72316024204421
oct376276573121
9107110788017
1034141304401
111352a970356
126749a2b381
1332b135c789
14191c462481
15d4c4b20a1
hex7f2faf651

34141304401 has 2 divisors, whose sum is σ = 34141304402. Its totient is φ = 34141304400.

The previous prime is 34141304399. The next prime is 34141304419. The reversal of 34141304401 is 10440314143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29328275025 + 4813029376 = 171255^2 + 69376^2 .

It is a cyclic number.

It is not a de Polignac number, because 34141304401 - 21 = 34141304399 is a prime.

It is a super-3 number, since 3×341413044013 (a number of 33 digits) contains 333 as substring.

Together with 34141304399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (34141301401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17070652200 + 17070652201.

It is an arithmetic number, because the mean of its divisors is an integer number (17070652201).

Almost surely, 234141304401 is an apocalyptic number.

It is an amenable number.

34141304401 is a deficient number, since it is larger than the sum of its proper divisors (1).

34141304401 is an equidigital number, since it uses as much as digits as its factorization.

34141304401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 34141304401 its reverse (10440314143), we get a palindrome (44581618544).

The spelling of 34141304401 in words is "thirty-four billion, one hundred forty-one million, three hundred four thousand, four hundred one".