Base | Representation |
---|---|
bin | 110001101011101111100… |
… | …000101001000001110111 |
3 | 110002101201000200121001221 |
4 | 301223233200221001313 |
5 | 421414311410004221 |
6 | 11132245545531211 |
7 | 501445420042552 |
oct | 61535740510167 |
9 | 13071630617057 |
10 | 3414222344311 |
11 | 10a6a66560939 |
12 | 4718481a3b07 |
13 | 1b9c6285889c |
14 | bb36bccd699 |
15 | 5dc29a40541 |
hex | 31aef829077 |
3414222344311 has 2 divisors, whose sum is σ = 3414222344312. Its totient is φ = 3414222344310.
The previous prime is 3414222344303. The next prime is 3414222344369. The reversal of 3414222344311 is 1134432224143.
It is a weak prime.
It is an emirp because it is prime and its reverse (1134432224143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3414222344311 - 23 = 3414222344303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3414222344371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707111172155 + 1707111172156.
It is an arithmetic number, because the mean of its divisors is an integer number (1707111172156).
Almost surely, 23414222344311 is an apocalyptic number.
3414222344311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3414222344311 is an equidigital number, since it uses as much as digits as its factorization.
3414222344311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 34.
Adding to 3414222344311 its reverse (1134432224143), we get a palindrome (4548654568454).
The spelling of 3414222344311 in words is "three trillion, four hundred fourteen billion, two hundred twenty-two million, three hundred forty-four thousand, three hundred eleven".
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