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341451415301993 is a prime number
BaseRepresentation
bin100110110100011000101101…
…0010100010010111101101001
31122202222102210012211100121122
41031220301122110102331221
5324223314444304130433
63210112340435345025
7131631023244203363
oct11550613224227551
91582872705740548
10341451415301993
11998848063551a7
12323676a4152175
131186a965621859
14604649dbc3d33
152971e05449198
hex1368c5a512f69

341451415301993 has 2 divisors, whose sum is σ = 341451415301994. Its totient is φ = 341451415301992.

The previous prime is 341451415301981. The next prime is 341451415302007. The reversal of 341451415301993 is 399103514154143.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 257249264376064 + 84202150925929 = 16038992^2 + 9176173^2 .

It is a cyclic number.

It is not a de Polignac number, because 341451415301993 - 212 = 341451415297897 is a prime.

It is not a weakly prime, because it can be changed into another prime (341451415301693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170725707650996 + 170725707650997.

It is an arithmetic number, because the mean of its divisors is an integer number (170725707650997).

Almost surely, 2341451415301993 is an apocalyptic number.

It is an amenable number.

341451415301993 is a deficient number, since it is larger than the sum of its proper divisors (1).

341451415301993 is an equidigital number, since it uses as much as digits as its factorization.

341451415301993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3499200, while the sum is 53.

The spelling of 341451415301993 in words is "three hundred forty-one trillion, four hundred fifty-one billion, four hundred fifteen million, three hundred one thousand, nine hundred ninety-three".