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34145522554143 = 371113531638531543
BaseRepresentation
bin1111100001110000111111…
…01111100001010100011111
311110220021120011202011020210
413300320133233201110133
513433420012233213033
6200342123030343503
710122634610610510
oct760703757412437
9143807504664223
1034145522554143
11a9750423454a0
1239b576a4bab93
131608ba7ca9490
1486091b562a07
153e330b72cd63
hex1f0e1fbe151f

34145522554143 has 256 divisors, whose sum is σ = 62777213485056. Its totient is φ = 15936935639040.

The previous prime is 34145522554141. The next prime is 34145522554147.

It is a happy number.

34145522554143 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 34145522554143 - 21 = 34145522554141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34145522554092 and 34145522554101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34145522554141) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 22129307430 + ... + 22129308972.

It is an arithmetic number, because the mean of its divisors is an integer number (245223490176).

Almost surely, 234145522554143 is an apocalyptic number.

34145522554143 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

34145522554143 is a deficient number, since it is larger than the sum of its proper divisors (28631690930913).

34145522554143 is a wasteful number, since it uses less digits than its factorization.

34145522554143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2646.

The product of its digits is 5760000, while the sum is 48.

It can be divided in two parts, 3414552 and 2554143, that added together give a palindrome (5968695).

The spelling of 34145522554143 in words is "thirty-four trillion, one hundred forty-five billion, five hundred twenty-two million, five hundred fifty-four thousand, one hundred forty-three".