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34151131151 is a prime number
BaseRepresentation
bin11111110011100100…
…001110100000001111
310021011001101012210022
4133303210032200033
51024420142144101
623404441132355
72316203553014
oct376344164017
9107131335708
1034151131151
1113535472335
12675118a0bb
1332b33c0517
14191d89d70b
15d4d2a3a1b
hex7f390e80f

34151131151 has 2 divisors, whose sum is σ = 34151131152. Its totient is φ = 34151131150.

The previous prime is 34151131127. The next prime is 34151131153. The reversal of 34151131151 is 15113115143.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34151131151 is a prime.

It is a super-3 number, since 3×341511311513 (a number of 33 digits) contains 333 as substring.

Together with 34151131153, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34151131151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34151131153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17075565575 + 17075565576.

It is an arithmetic number, because the mean of its divisors is an integer number (17075565576).

Almost surely, 234151131151 is an apocalyptic number.

34151131151 is a deficient number, since it is larger than the sum of its proper divisors (1).

34151131151 is an equidigital number, since it uses as much as digits as its factorization.

34151131151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 900, while the sum is 26.

Adding to 34151131151 its reverse (15113115143), we get a palindrome (49264246294).

The spelling of 34151131151 in words is "thirty-four billion, one hundred fifty-one million, one hundred thirty-one thousand, one hundred fifty-one".