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3416202141047 is a prime number
BaseRepresentation
bin110001101101100101100…
…000111101110101110111
3110002120211000000200121222
4301231211200331311313
5421432340222003142
611133214231500555
7501545450040653
oct61554540756567
913076730020558
103416202141047
1110a7892059493
124720bb22775b
131ba1b9a7b147
14bb4b8c09a63
155dce3761bd2
hex31b6583dd77

3416202141047 has 2 divisors, whose sum is σ = 3416202141048. Its totient is φ = 3416202141046.

The previous prime is 3416202141029. The next prime is 3416202141049. The reversal of 3416202141047 is 7401412026143.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3416202141047 - 232 = 3411907173751 is a prime.

Together with 3416202141049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3416202140998 and 3416202141016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3416202141049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1708101070523 + 1708101070524.

It is an arithmetic number, because the mean of its divisors is an integer number (1708101070524).

Almost surely, 23416202141047 is an apocalyptic number.

3416202141047 is a deficient number, since it is larger than the sum of its proper divisors (1).

3416202141047 is an equidigital number, since it uses as much as digits as its factorization.

3416202141047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 35.

The spelling of 3416202141047 in words is "three trillion, four hundred sixteen billion, two hundred two million, one hundred forty-one thousand, forty-seven".