Base | Representation |
---|---|
bin | 1111100011011000101110… |
… | …01110000001011101111000 |
3 | 11111002121022102021100012221 |
4 | 13301230113032001131320 |
5 | 13440323041304130130 |
6 | 200423453150213424 |
7 | 10126645653315136 |
oct | 761542716013570 |
9 | 144077272240187 |
10 | 34201214130040 |
11 | a996720830781 |
12 | 3a045114b4274 |
13 | 1611211c57999 |
14 | 8634c1b38756 |
15 | 3e49baad587a |
hex | 1f1b17381778 |
34201214130040 has 16 divisors (see below), whose sum is σ = 76952731792680. Its totient is φ = 13680485652000.
The previous prime is 34201214130011. The next prime is 34201214130043. The reversal of 34201214130040 is 4003141210243.
It is a super-4 number, since 4×342012141300404 (a number of 55 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34201214129987 and 34201214130014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34201214130043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427515176586 + ... + 427515176665.
Almost surely, 234201214130040 is an apocalyptic number.
It is an amenable number.
34201214130040 is an abundant number, since it is smaller than the sum of its proper divisors (42751517662640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
34201214130040 is a wasteful number, since it uses less digits than its factorization.
34201214130040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 855030353262 (or 855030353258 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 34201214130040 its reverse (4003141210243), we get a palindrome (38204355340283).
The spelling of 34201214130040 in words is "thirty-four trillion, two hundred one billion, two hundred fourteen million, one hundred thirty thousand, forty".
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