Base | Representation |
---|---|
bin | 1001111101111101001… |
… | …10101111010100110101 |
3 | 1012202001102122001111121 |
4 | 10332332212233110311 |
5 | 21102420030231431 |
6 | 421201544503541 |
7 | 33513322012516 |
oct | 4767646572465 |
9 | 1182042561447 |
10 | 342500242741 |
11 | 122287504758 |
12 | 5646677abb1 |
13 | 263b3b96c37 |
14 | 128117c4a0d |
15 | 8d9891d611 |
hex | 4fbe9af535 |
342500242741 has 2 divisors, whose sum is σ = 342500242742. Its totient is φ = 342500242740.
The previous prime is 342500242699. The next prime is 342500242759. The reversal of 342500242741 is 147242005243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 339485683716 + 3014559025 = 582654^2 + 54905^2 .
It is a cyclic number.
It is not a de Polignac number, because 342500242741 - 215 = 342500209973 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 342500242697 and 342500242706.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (342500242781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171250121370 + 171250121371.
It is an arithmetic number, because the mean of its divisors is an integer number (171250121371).
Almost surely, 2342500242741 is an apocalyptic number.
It is an amenable number.
342500242741 is a deficient number, since it is larger than the sum of its proper divisors (1).
342500242741 is an equidigital number, since it uses as much as digits as its factorization.
342500242741 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 53760, while the sum is 34.
Adding to 342500242741 its reverse (147242005243), we get a palindrome (489742247984).
The spelling of 342500242741 in words is "three hundred forty-two billion, five hundred million, two hundred forty-two thousand, seven hundred forty-one".
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