Base | Representation |
---|---|
bin | 110001110101110010000… |
… | …011011010101001110111 |
3 | 110010102112022022211220021 |
4 | 301311302003122221313 |
5 | 422103401110330033 |
6 | 11141231400350011 |
7 | 502306516222144 |
oct | 61656203325167 |
9 | 13112468284807 |
10 | 3425002433143 |
11 | 1100598647165 |
12 | 473956475307 |
13 | 1bac90047085 |
14 | bbab18b73cb |
15 | 5e15b140b2d |
hex | 31d720daa77 |
3425002433143 has 2 divisors, whose sum is σ = 3425002433144. Its totient is φ = 3425002433142.
The previous prime is 3425002433117. The next prime is 3425002433159. The reversal of 3425002433143 is 3413342005243.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3425002433143 - 237 = 3287563479671 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3425002433099 and 3425002433108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3425002443143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712501216571 + 1712501216572.
It is an arithmetic number, because the mean of its divisors is an integer number (1712501216572).
Almost surely, 23425002433143 is an apocalyptic number.
3425002433143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3425002433143 is an equidigital number, since it uses as much as digits as its factorization.
3425002433143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 34.
Adding to 3425002433143 its reverse (3413342005243), we get a palindrome (6838344438386).
The spelling of 3425002433143 in words is "three trillion, four hundred twenty-five billion, two million, four hundred thirty-three thousand, one hundred forty-three".
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