Base | Representation |
---|---|
bin | 1111100111001010101010… |
… | …00101000111011011000101 |
3 | 11111120000120110100001112121 |
4 | 13303211111011013123011 |
5 | 13444440043324021123 |
6 | 201003253504445541 |
7 | 10142224454440336 |
oct | 763452505073305 |
9 | 144500513301477 |
10 | 34331101001413 |
11 | aa36813561677 |
12 | 3a257203198b1 |
13 | 16205415700a8 |
14 | 8698c419628d |
15 | 3e806da4e75d |
hex | 1f39551476c5 |
34331101001413 has 2 divisors, whose sum is σ = 34331101001414. Its totient is φ = 34331101001412.
The previous prime is 34331101001363. The next prime is 34331101001443. The reversal of 34331101001413 is 31410010113343.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28606216916484 + 5724884084929 = 5348478^2 + 2392673^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34331101001413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34331101001443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17165550500706 + 17165550500707.
It is an arithmetic number, because the mean of its divisors is an integer number (17165550500707).
Almost surely, 234331101001413 is an apocalyptic number.
It is an amenable number.
34331101001413 is a deficient number, since it is larger than the sum of its proper divisors (1).
34331101001413 is an equidigital number, since it uses as much as digits as its factorization.
34331101001413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 34331101001413 its reverse (31410010113343), we get a palindrome (65741111114756).
The spelling of 34331101001413 in words is "thirty-four trillion, three hundred thirty-one billion, one hundred one million, one thousand, four hundred thirteen".
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