Base | Representation |
---|---|
bin | 100111000010000000101111… |
… | …1000001111111100111100100 |
3 | 1200000121110111211201102101101 |
4 | 1032010001133001333213210 |
5 | 330000010224113200200 |
6 | 3214104525250405444 |
7 | 132213230153463661 |
oct | 11604013701774744 |
9 | 1600543454642341 |
10 | 343324100131300 |
11 | 9a436a2a0a0952 |
12 | 3260a616590884 |
13 | 119754292b58a2 |
14 | 60acd919aca68 |
15 | 29a59ab14d26a |
hex | 138405f07f9e4 |
343324100131300 has 36 divisors (see below), whose sum is σ = 760864644046080. Its totient is φ = 134407732815520.
The previous prime is 343324100131279. The next prime is 343324100131301. The reversal of 343324100131300 is 3131001423343.
It is not an unprimeable number, because it can be changed into a prime (343324100131301) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 36523835740 + ... + 36523845139.
It is an arithmetic number, because the mean of its divisors is an integer number (21135129001280).
Almost surely, 2343324100131300 is an apocalyptic number.
It is an amenable number.
343324100131300 is an abundant number, since it is smaller than the sum of its proper divisors (417540543914780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
343324100131300 is a wasteful number, since it uses less digits than its factorization.
343324100131300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73047680940 (or 73047680933 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 343324100131300 its reverse (3131001423343), we get a palindrome (346455101554643).
The spelling of 343324100131300 in words is "three hundred forty-three trillion, three hundred twenty-four billion, one hundred million, one hundred thirty-one thousand, three hundred".
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