343410121213 has 2 divisors, whose sum is σ = 343410121214. Its totient is φ = 343410121212.

The previous prime is 343410121151. The next prime is 343410121231. The reversal of 343410121213 is 312121014343.

Together with next prime (343410121231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 325974767364 + 17435353849 = 570942^2 + 132043^2 .

It is an emirp because it is prime and its reverse (312121014343) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 343410121213 - 2¹⁷ = 343409990141 is a prime.

It is a super-2 number, since 2×343410121213² (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (343410121253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171705060606 + 171705060607.

It is an arithmetic number, because the mean of its divisors is an integer number (171705060607).

Almost surely, 2^343410121213 is an apocalyptic number.

It is an amenable number.

343410121213 is a deficient number, since it is larger than the sum of its proper divisors (1).

343410121213 is an equidigital number, since it uses as much as digits as its factorization.

343410121213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 343410121213 its reverse (312121014343), we get a palindrome (655531135556).

The spelling of 343410121213 in words is "three hundred forty-three billion, four hundred ten million, one hundred twenty-one thousand, two hundred thirteen".