Base | Representation |
---|---|
bin | 110001111110011111010… |
… | …111001110001101000111 |
3 | 110011022122221012012110201 |
4 | 301332133113032031013 |
5 | 422232023222044333 |
6 | 11145415245431331 |
7 | 503060312611333 |
oct | 61763727161507 |
9 | 13138587165421 |
10 | 3434352534343 |
11 | 1104556521625 |
12 | 47572586b547 |
13 | 1bbb201b7633 |
14 | bc31b5c47c3 |
15 | 5e506e2617d |
hex | 31f9f5ce347 |
3434352534343 has 2 divisors, whose sum is σ = 3434352534344. Its totient is φ = 3434352534342.
The previous prime is 3434352534341. The next prime is 3434352534377.
3434352534343 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 3434352534343 - 21 = 3434352534341 is a prime.
Together with 3434352534341, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 3434352534293 and 3434352534302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3434352534341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1717176267171 + 1717176267172.
It is an arithmetic number, because the mean of its divisors is an integer number (1717176267172).
Almost surely, 23434352534343 is an apocalyptic number.
3434352534343 is a deficient number, since it is larger than the sum of its proper divisors (1).
3434352534343 is an equidigital number, since it uses as much as digits as its factorization.
3434352534343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9331200, while the sum is 46.
The spelling of 3434352534343 in words is "three trillion, four hundred thirty-four billion, three hundred fifty-two million, five hundred thirty-four thousand, three hundred forty-three".
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