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34345441533407 is a prime number
BaseRepresentation
bin1111100111100101010111…
…10101111001110111011111
311111121101120212120120012012
413303302223311321313133
514000203431013032112
6201014024504101435
710143243026110454
oct763625365716737
9144541525516165
1034345441533407
11aa419023a8604
123a28462a6487b
1316219b859b794
1486a48499382b
153e860c9eb022
hex1f3cabd79ddf

34345441533407 has 2 divisors, whose sum is σ = 34345441533408. Its totient is φ = 34345441533406.

The previous prime is 34345441533371. The next prime is 34345441533457. The reversal of 34345441533407 is 70433514454343.

It is an a-pointer prime, because the next prime (34345441533457) can be obtained adding 34345441533407 to its sum of digits (50).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 34345441533407 - 26 = 34345441533343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34345441533457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17172720766703 + 17172720766704.

It is an arithmetic number, because the mean of its divisors is an integer number (17172720766704).

Almost surely, 234345441533407 is an apocalyptic number.

34345441533407 is a deficient number, since it is larger than the sum of its proper divisors (1).

34345441533407 is an equidigital number, since it uses as much as digits as its factorization.

34345441533407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14515200, while the sum is 50.

The spelling of 34345441533407 in words is "thirty-four trillion, three hundred forty-five billion, four hundred forty-one million, five hundred thirty-three thousand, four hundred seven".