Base | Representation |
---|---|
bin | 1001111111110101100… |
… | …11111101010111111001 |
3 | 1012211122211022100222102 |
4 | 10333322303331113321 |
5 | 21112002121403423 |
6 | 421450110433145 |
7 | 33550335502652 |
oct | 4777263752771 |
9 | 1184584270872 |
10 | 343510341113 |
11 | 1227556a55a5 |
12 | 566a8b027b5 |
13 | 2651522b694 |
14 | 128a9a00529 |
15 | 8e07446c28 |
hex | 4ffacfd5f9 |
343510341113 has 2 divisors, whose sum is σ = 343510341114. Its totient is φ = 343510341112.
The previous prime is 343510341107. The next prime is 343510341121. The reversal of 343510341113 is 311143015343.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 342724772329 + 785568784 = 585427^2 + 28028^2 .
It is a cyclic number.
It is not a de Polignac number, because 343510341113 - 26 = 343510341049 is a prime.
It is not a weakly prime, because it can be changed into another prime (343510341143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171755170556 + 171755170557.
It is an arithmetic number, because the mean of its divisors is an integer number (171755170557).
Almost surely, 2343510341113 is an apocalyptic number.
It is an amenable number.
343510341113 is a deficient number, since it is larger than the sum of its proper divisors (1).
343510341113 is an equidigital number, since it uses as much as digits as its factorization.
343510341113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 343510341113 its reverse (311143015343), we get a palindrome (654653356456).
The spelling of 343510341113 in words is "three hundred forty-three billion, five hundred ten million, three hundred forty-one thousand, one hundred thirteen".
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