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3436545443453 is a prime number
BaseRepresentation
bin110010000000100010000…
…100100000011001111101
3110011112022202112112020122
4302000202010200121331
5422301021113142303
611150421023224325
7503165541205343
oct62004204403175
913145282475218
103436545443453
111105481348701
124760381480a5
131bc0ac6055a5
14bc488937993
155e5d46e1e38
hex3202212067d

3436545443453 has 2 divisors, whose sum is σ = 3436545443454. Its totient is φ = 3436545443452.

The previous prime is 3436545443431. The next prime is 3436545443491. The reversal of 3436545443453 is 3543445456343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2384562905209 + 1051982538244 = 1544203^2 + 1025662^2 .

It is a cyclic number.

It is not a de Polignac number, because 3436545443453 - 238 = 3161667536509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3436545443395 and 3436545443404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3436545443413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1718272721726 + 1718272721727.

It is an arithmetic number, because the mean of its divisors is an integer number (1718272721727).

Almost surely, 23436545443453 is an apocalyptic number.

It is an amenable number.

3436545443453 is a deficient number, since it is larger than the sum of its proper divisors (1).

3436545443453 is an equidigital number, since it uses as much as digits as its factorization.

3436545443453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 62208000, while the sum is 53.

The spelling of 3436545443453 in words is "three trillion, four hundred thirty-six billion, five hundred forty-five million, four hundred forty-three thousand, four hundred fifty-three".