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3439804921344 = 29351147531009
BaseRepresentation
bin110010000011100100010…
…110011011011000000000
3110011211201220211011100000
4302003210112123120000
5422324210024440334
611152120301200000
7503342400256341
oct62034426333000
913154656734300
103439804921344
1111068a4225690
124767a7860000
131bc4ab99a52c
14bc6b77a60c8
155e72593d299
hex320e459b600

3439804921344 has 960 divisors, whose sum is σ = 11698081274880. Its totient is φ = 999946321920.

The previous prime is 3439804921331. The next prime is 3439804921363. The reversal of 3439804921344 is 4431294089343.

3439804921344 is a `hidden beast` number, since 3 + 4 + 39 + 80 + 492 + 1 + 3 + 44 = 666.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3409122312 + ... + 3409123320.

It is an arithmetic number, because the mean of its divisors is an integer number (12185501328).

Almost surely, 23439804921344 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3439804921344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5849040637440).

3439804921344 is an abundant number, since it is smaller than the sum of its proper divisors (8258276353536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3439804921344 is a wasteful number, since it uses less digits than its factorization.

3439804921344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1153 (or 1125 counting only the distinct ones).

The product of its (nonzero) digits is 8957952, while the sum is 54.

The spelling of 3439804921344 in words is "three trillion, four hundred thirty-nine billion, eight hundred four million, nine hundred twenty-one thousand, three hundred forty-four".