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344000502051413 is a prime number
BaseRepresentation
bin100111000110111011101101…
…1101110100011001001010101
31200010000010102110021011011112
41032031313123232203021111
5330042101012011121123
63215343352103144405
7132313134061106534
oct11615673356431125
91603003373234145
10344000502051413
119a677880373889
12326b9728145105
13119c41537baa3c
1460d39dabbc31b
1529b8398656d78
hex138dddbba3255

344000502051413 has 2 divisors, whose sum is σ = 344000502051414. Its totient is φ = 344000502051412.

The previous prime is 344000502051403. The next prime is 344000502051463. The reversal of 344000502051413 is 314150205000443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 328111851644164 + 15888650407249 = 18113858^2 + 3986057^2 .

It is a cyclic number.

It is not a de Polignac number, because 344000502051413 - 222 = 344000497857109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 344000502051413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (344000502051403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172000251025706 + 172000251025707.

It is an arithmetic number, because the mean of its divisors is an integer number (172000251025707).

Almost surely, 2344000502051413 is an apocalyptic number.

It is an amenable number.

344000502051413 is a deficient number, since it is larger than the sum of its proper divisors (1).

344000502051413 is an equidigital number, since it uses as much as digits as its factorization.

344000502051413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 344000502051413 its reverse (314150205000443), we get a palindrome (658150707051856).

The spelling of 344000502051413 in words is "three hundred forty-four trillion, five hundred two million, fifty-one thousand, four hundred thirteen".