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3440230654247 is a prime number
BaseRepresentation
bin110010000011111101101…
…110011110000100100111
3110011212211120220122002022
4302003331232132010213
5422331043021413442
611152230430133355
7503356060035212
oct62037556360447
913155746818068
103440230654247
111106aa2577062
124768a635125b
131bc548c4b7aa
14bc718148779
155e74ced63d2
hex320fdb9e127

3440230654247 has 2 divisors, whose sum is σ = 3440230654248. Its totient is φ = 3440230654246.

The previous prime is 3440230654177. The next prime is 3440230654249. The reversal of 3440230654247 is 7424560320443.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3440230654247 - 238 = 3165352747303 is a prime.

Together with 3440230654249, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3440230654198 and 3440230654207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3440230654249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720115327123 + 1720115327124.

It is an arithmetic number, because the mean of its divisors is an integer number (1720115327124).

Almost surely, 23440230654247 is an apocalyptic number.

3440230654247 is a deficient number, since it is larger than the sum of its proper divisors (1).

3440230654247 is an equidigital number, since it uses as much as digits as its factorization.

3440230654247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1935360, while the sum is 44.

The spelling of 3440230654247 in words is "three trillion, four hundred forty billion, two hundred thirty million, six hundred fifty-four thousand, two hundred forty-seven".