Base | Representation |
---|---|
bin | 100111001001010101110000… |
… | …1100011010001011100111000 |
3 | 1200011011202022011222221200202 |
4 | 1032102223201203101130320 |
5 | 330113011011413143230 |
6 | 3220155342053421332 |
7 | 132346054624242200 |
oct | 11622534143213470 |
9 | 1604152264887622 |
10 | 344331312240440 |
11 | 9a7950a9074118 |
12 | 3275186b93a848 |
13 | 11a193c37c1215 |
14 | 6105a1dbc7400 |
15 | 29c1caab2aa45 |
hex | 1392ae18d1738 |
344331312240440 has 48 divisors (see below), whose sum is σ = 901234506022200. Its totient is φ = 118056449910336.
The previous prime is 344331312240413. The next prime is 344331312240451. The reversal of 344331312240440 is 44042213133443.
It is a junction number, because it is equal to n+sod(n) for n = 344331312240394 and 344331312240403.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 87839618510 + ... + 87839622429.
Almost surely, 2344331312240440 is an apocalyptic number.
It is an amenable number.
344331312240440 is an abundant number, since it is smaller than the sum of its proper divisors (556903193781760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
344331312240440 is a wasteful number, since it uses less digits than its factorization.
344331312240440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175679240964 (or 175679240953 counting only the distinct ones).
The product of its (nonzero) digits is 331776, while the sum is 38.
Adding to 344331312240440 its reverse (44042213133443), we get a palindrome (388373525373883).
The spelling of 344331312240440 in words is "three hundred forty-four trillion, three hundred thirty-one billion, three hundred twelve million, two hundred forty thousand, four hundred forty".
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