Base | Representation |
---|---|
bin | 1010000001100001011… |
… | …00101111110101001111 |
3 | 1012220222211111100110212 |
4 | 11000300230233311033 |
5 | 21120330042422203 |
6 | 422115524153035 |
7 | 33611624161232 |
oct | 5006054576517 |
9 | 1186884440425 |
10 | 344414420303 |
11 | 123079a63688 |
12 | 568bb83877b |
13 | 2662a622995 |
14 | 12953add419 |
15 | 8e5b9cc1d8 |
hex | 5030b2fd4f |
344414420303 has 2 divisors, whose sum is σ = 344414420304. Its totient is φ = 344414420302.
The previous prime is 344414420297. The next prime is 344414420347. The reversal of 344414420303 is 303024414443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 344414420303 - 214 = 344414403919 is a prime.
It is a super-2 number, since 2×3444144203032 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 344414420303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (344414420393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172207210151 + 172207210152.
It is an arithmetic number, because the mean of its divisors is an integer number (172207210152).
Almost surely, 2344414420303 is an apocalyptic number.
344414420303 is a deficient number, since it is larger than the sum of its proper divisors (1).
344414420303 is an equidigital number, since it uses as much as digits as its factorization.
344414420303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 344414420303 its reverse (303024414443), we get a palindrome (647438834746).
The spelling of 344414420303 in words is "three hundred forty-four billion, four hundred fourteen million, four hundred twenty thousand, three hundred three".
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