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345055200001 is a prime number
BaseRepresentation
bin1010000010101101110…
…01001000001100000001
31012222122111020022222021
411001112321020030001
521123133112400001
6422303254241441
733633534543511
oct5012671101401
91188574208867
10345055200001
11123378734986
1256a5a356281
13267002c8c75
14129b4c5d841
158e97da2ba1
hex5056e48301

345055200001 has 2 divisors, whose sum is σ = 345055200002. Its totient is φ = 345055200000.

The previous prime is 345055199999. The next prime is 345055200011. The reversal of 345055200001 is 100002550543.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 214679322225 + 130375877776 = 463335^2 + 361076^2 .

It is a cyclic number.

It is not a de Polignac number, because 345055200001 - 21 = 345055199999 is a prime.

It is a super-2 number, since 2×3450552000012 (a number of 24 digits) contains 22 as substring.

Together with 345055199999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (345055200011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172527600000 + 172527600001.

It is an arithmetic number, because the mean of its divisors is an integer number (172527600001).

Almost surely, 2345055200001 is an apocalyptic number.

It is an amenable number.

345055200001 is a deficient number, since it is larger than the sum of its proper divisors (1).

345055200001 is an equidigital number, since it uses as much as digits as its factorization.

345055200001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3000, while the sum is 25.

Adding to 345055200001 its reverse (100002550543), we get a palindrome (445057750544).

The spelling of 345055200001 in words is "three hundred forty-five billion, fifty-five million, two hundred thousand, one".