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345421504889 is a prime number
BaseRepresentation
bin1010000011011001011…
…10011110000101111001
31020000121000111112210222
411001230232132011321
521124410401124024
6422403501345425
733645603230006
oct5015456360571
91200530445728
10345421504889
1112354648619a
1256b40b68275
132675b170716
1412a0b7728ad
158eba10c85e
hex506cb9e179

345421504889 has 2 divisors, whose sum is σ = 345421504890. Its totient is φ = 345421504888.

The previous prime is 345421504823. The next prime is 345421504891. The reversal of 345421504889 is 988405124543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 302285538025 + 43135966864 = 549805^2 + 207692^2 .

It is an emirp because it is prime and its reverse (988405124543) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-345421504889 is a prime.

Together with 345421504891, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 345421504889.

It is not a weakly prime, because it can be changed into another prime (345421504789) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172710752444 + 172710752445.

It is an arithmetic number, because the mean of its divisors is an integer number (172710752445).

Almost surely, 2345421504889 is an apocalyptic number.

It is an amenable number.

345421504889 is a deficient number, since it is larger than the sum of its proper divisors (1).

345421504889 is an equidigital number, since it uses as much as digits as its factorization.

345421504889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5529600, while the sum is 53.

The spelling of 345421504889 in words is "three hundred forty-five billion, four hundred twenty-one million, five hundred four thousand, eight hundred eighty-nine".