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34544301131 is a prime number
BaseRepresentation
bin100000001011000000…
…000011010001001011
310022011110012022121102
4200023000003101023
51031221320114011
623511444132015
72332016500124
oct401300032113
9108143168542
1034544301131
11137173a27aa
12684099700b
1333469b0092
141959ba704b
15d72a6873b
hex80b00344b

34544301131 has 2 divisors, whose sum is σ = 34544301132. Its totient is φ = 34544301130.

The previous prime is 34544301119. The next prime is 34544301133. The reversal of 34544301131 is 13110344543.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 34544301131 - 26 = 34544301067 is a prime.

It is a super-2 number, since 2×345443011312 (a number of 22 digits) contains 22 as substring.

Together with 34544301133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 34544301094 and 34544301103.

It is not a weakly prime, because it can be changed into another prime (34544301133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17272150565 + 17272150566.

It is an arithmetic number, because the mean of its divisors is an integer number (17272150566).

Almost surely, 234544301131 is an apocalyptic number.

34544301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

34544301131 is an equidigital number, since it uses as much as digits as its factorization.

34544301131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 34544301131 its reverse (13110344543), we get a palindrome (47654645674).

The spelling of 34544301131 in words is "thirty-four billion, five hundred forty-four million, three hundred one thousand, one hundred thirty-one".