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3480051125693 is a prime number
BaseRepresentation
bin110010101001000011001…
…101100000110110111101
3110022200121202011011201002
4302221003031200312331
5424004121042010233
611222414033100045
7506265624333152
oct62510315406675
913280552134632
103480051125693
11112197715469a
1248255a0b7625
131c3223a6392c
14c0614942229
15607cdd596e8
hex32a43360dbd

3480051125693 has 2 divisors, whose sum is σ = 3480051125694. Its totient is φ = 3480051125692.

The previous prime is 3480051125689. The next prime is 3480051125711. The reversal of 3480051125693 is 3965211500843.

3480051125693 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3334140877369 + 145910248324 = 1825963^2 + 381982^2 .

It is a cyclic number.

It is not a de Polignac number, because 3480051125693 - 22 = 3480051125689 is a prime.

It is a super-2 number, since 2×34800511256932 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3480051125093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740025562846 + 1740025562847.

It is an arithmetic number, because the mean of its divisors is an integer number (1740025562847).

Almost surely, 23480051125693 is an apocalyptic number.

It is an amenable number.

3480051125693 is a deficient number, since it is larger than the sum of its proper divisors (1).

3480051125693 is an equidigital number, since it uses as much as digits as its factorization.

3480051125693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 777600, while the sum is 47.

The spelling of 3480051125693 in words is "three trillion, four hundred eighty billion, fifty-one million, one hundred twenty-five thousand, six hundred ninety-three".