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350000113 is a prime number
BaseRepresentation
bin10100110111001…
…001001111110001
3220101120211220011
4110313021033301
51204100000423
654421414521
711446644331
oct2467111761
9811524804
10350000113
1116a6252a1
129926a441
1357686278
14346ab0c1
1520ad8b0d
hex14dc93f1

350000113 has 2 divisors, whose sum is σ = 350000114. Its totient is φ = 350000112.

The previous prime is 350000111. The next prime is 350000129. The reversal of 350000113 is 311000053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 279825984 + 70174129 = 16728^2 + 8377^2 .

It is a cyclic number.

It is not a de Polignac number, because 350000113 - 21 = 350000111 is a prime.

Together with 350000111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 350000093 and 350000102.

It is not a weakly prime, because it can be changed into another prime (350000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175000056 + 175000057.

It is an arithmetic number, because the mean of its divisors is an integer number (175000057).

Almost surely, 2350000113 is an apocalyptic number.

It is an amenable number.

350000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

350000113 is an equidigital number, since it uses as much as digits as its factorization.

350000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 350000113 is about 18708.2899539215. The cubic root of 350000113 is about 704.7299490488.

Adding to 350000113 its reverse (311000053), we get a palindrome (661000166).

The spelling of 350000113 in words is "three hundred fifty million, one hundred thirteen", and thus it is an aban number.