350000111 has 2 divisors, whose sum is σ = 350000112. Its totient is φ = 350000110.

The previous prime is 350000089. The next prime is 350000113. The reversal of 350000111 is 111000053.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 350000111 - 2¹⁰ = 349999087 is a prime.

Together with 350000113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 350000092 and 350000101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (350000113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175000055 + 175000056.

It is an arithmetic number, because the mean of its divisors is an integer number (175000056).

Almost surely, 2^350000111 is an apocalyptic number.

350000111 is a deficient number, since it is larger than the sum of its proper divisors (1).

350000111 is an equidigital number, since it uses as much as digits as its factorization.

350000111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 350000111 is about 18708.2899004693. The cubic root of 350000111 is about 704.7299477065.

Adding to 350000111 its reverse (111000053), we get a palindrome (461000164).

The spelling of 350000111 in words is "three hundred fifty million, one hundred eleven", and thus it is an aban number.