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3500125255381 is a prime number
BaseRepresentation
bin110010111011101111101…
…110001111011011010101
3110101121102202011121202211
4302323233232033123111
5424321224031133011
611235534011233421
7510606236533456
oct62735756173325
913347382147684
103500125255381
11112a438505417
12486420a48871
131c50a28c4991
14c159aa0312d
15610a6369b21
hex32eefb8f6d5

3500125255381 has 2 divisors, whose sum is σ = 3500125255382. Its totient is φ = 3500125255380.

The previous prime is 3500125255369. The next prime is 3500125255441. The reversal of 3500125255381 is 1835525210053.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2357941442481 + 1142183812900 = 1535559^2 + 1068730^2 .

It is a cyclic number.

It is not a de Polignac number, because 3500125255381 - 25 = 3500125255349 is a prime.

It is a super-2 number, since 2×35001252553812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3500125252381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1750062627690 + 1750062627691.

It is an arithmetic number, because the mean of its divisors is an integer number (1750062627691).

Almost surely, 23500125255381 is an apocalyptic number.

It is an amenable number.

3500125255381 is a deficient number, since it is larger than the sum of its proper divisors (1).

3500125255381 is an equidigital number, since it uses as much as digits as its factorization.

3500125255381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

The spelling of 3500125255381 in words is "three trillion, five hundred billion, one hundred twenty-five million, two hundred fifty-five thousand, three hundred eighty-one".