Base | Representation |
---|---|
bin | 1101000100000010… |
… | …0111110101111100 |
3 | 100001101021210201201 |
4 | 3101000213311330 |
5 | 24140142220330 |
6 | 1335542345244 |
7 | 152616422344 |
oct | 32100476574 |
9 | 10041253651 |
10 | 3506601340 |
11 | 153a426540 |
12 | 81a42b224 |
13 | 43b63b248 |
14 | 2539d9d24 |
15 | 157cb2eca |
hex | d1027d7c |
3506601340 has 48 divisors (see below), whose sum is σ = 8037447264. Its totient is φ = 1274470400.
The previous prime is 3506601337. The next prime is 3506601359. The reversal of 3506601340 is 431066053.
3506601340 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3506601299 and 3506601308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 687600 + ... + 692680.
It is an arithmetic number, because the mean of its divisors is an integer number (167446818).
Almost surely, 23506601340 is an apocalyptic number.
It is an amenable number.
3506601340 is an abundant number, since it is smaller than the sum of its proper divisors (4530845924).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3506601340 is a wasteful number, since it uses less digits than its factorization.
3506601340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8238 (or 8236 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 28.
The square root of 3506601340 is about 59216.5630546049. The cubic root of 3506601340 is about 1519.2484367383.
Adding to 3506601340 its reverse (431066053), we get a palindrome (3937667393).
It can be divided in two parts, 35066013 and 40, that added together give a palindrome (35066053).
The spelling of 3506601340 in words is "three billion, five hundred six million, six hundred one thousand, three hundred forty".
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