Base | Representation |
---|---|
bin | 1111111101111011000111… |
… | …11011001010110111111111 |
3 | 11121022202212201102010022201 |
4 | 13332331203323022313333 |
5 | 14100242443212201343 |
6 | 202402412152452331 |
7 | 10252555501221142 |
oct | 776754373126777 |
9 | 147282781363281 |
10 | 35113034100223 |
11 | 1020839939a072 |
12 | 3b311840aa0a7 |
13 | 16791b6493c91 |
14 | 8956a0c78059 |
15 | 40d585b7094d |
hex | 1fef63ecadff |
35113034100223 has 2 divisors, whose sum is σ = 35113034100224. Its totient is φ = 35113034100222.
The previous prime is 35113034100163. The next prime is 35113034100247. The reversal of 35113034100223 is 32200143031153.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35113034100223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 35113034100191 and 35113034100200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35113034100283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17556517050111 + 17556517050112.
It is an arithmetic number, because the mean of its divisors is an integer number (17556517050112).
Almost surely, 235113034100223 is an apocalyptic number.
35113034100223 is a deficient number, since it is larger than the sum of its proper divisors (1).
35113034100223 is an equidigital number, since it uses as much as digits as its factorization.
35113034100223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 35113034100223 its reverse (32200143031153), we get a palindrome (67313177131376).
The spelling of 35113034100223 in words is "thirty-five trillion, one hundred thirteen billion, thirty-four million, one hundred thousand, two hundred twenty-three".
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