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35130425444143 is a prime number
BaseRepresentation
bin1111111110011011100001…
…00001111000011100101111
311121101102202202021221011121
413333031300201320130233
514101034102403203033
6202414410013401411
710254042456212551
oct777156041703457
9147342682257147
1035130425444143
1110214803351177
123b34618499267
13167aa28587a23
148964709074d1
1540dc5289b62d
hex1ff37087872f

35130425444143 has 2 divisors, whose sum is σ = 35130425444144. Its totient is φ = 35130425444142.

The previous prime is 35130425444141. The next prime is 35130425444159. The reversal of 35130425444143 is 34144452403153.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 35130425444143 - 21 = 35130425444141 is a prime.

Together with 35130425444141, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 35130425444143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35130425444141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17565212722071 + 17565212722072.

It is an arithmetic number, because the mean of its divisors is an integer number (17565212722072).

Almost surely, 235130425444143 is an apocalyptic number.

35130425444143 is a deficient number, since it is larger than the sum of its proper divisors (1).

35130425444143 is an equidigital number, since it uses as much as digits as its factorization.

35130425444143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1382400, while the sum is 43.

Adding to 35130425444143 its reverse (34144452403153), we get a palindrome (69274877847296).

The spelling of 35130425444143 in words is "thirty-five trillion, one hundred thirty billion, four hundred twenty-five million, four hundred forty-four thousand, one hundred forty-three".