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353151044143 is a prime number
BaseRepresentation
bin1010010001110010111…
…00010100101000101111
31020202112200222211022121
411020321130110220233
521241223131403033
6430122500253411
734341261226612
oct5107134245057
91222480884277
10353151044143
11126852615467
12585396a1267
13273c06590a1
1413142156179
1592bd9d162d
hex5239714a2f

353151044143 has 2 divisors, whose sum is σ = 353151044144. Its totient is φ = 353151044142.

The previous prime is 353151044123. The next prime is 353151044167. The reversal of 353151044143 is 341440151353.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-353151044143 is a prime.

It is a super-2 number, since 2×3531510441432 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 353151044099 and 353151044108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (353151044123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176575522071 + 176575522072.

It is an arithmetic number, because the mean of its divisors is an integer number (176575522072).

Almost surely, 2353151044143 is an apocalyptic number.

353151044143 is a deficient number, since it is larger than the sum of its proper divisors (1).

353151044143 is an equidigital number, since it uses as much as digits as its factorization.

353151044143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 353151044143 its reverse (341440151353), we get a palindrome (694591195496).

The spelling of 353151044143 in words is "three hundred fifty-three billion, one hundred fifty-one million, forty-four thousand, one hundred forty-three".