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354002031221 is a prime number
BaseRepresentation
bin1010010011011000010…
…10100101001001110101
31020211202000021110010112
411021230022211021311
521244444004444341
6430343140032405
734401333421526
oct5115412451165
91224660243115
10354002031221
11127149a10673
1258736692705
13274c7a51737
14131c319484d
15931d57aaeb
hex526c2a5275

354002031221 has 2 divisors, whose sum is σ = 354002031222. Its totient is φ = 354002031220.

The previous prime is 354002031209. The next prime is 354002031223. The reversal of 354002031221 is 122130200453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 353889352996 + 112678225 = 594886^2 + 10615^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354002031221 is a prime.

It is a Sophie Germain prime.

Together with 354002031223, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354002031223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177001015610 + 177001015611.

It is an arithmetic number, because the mean of its divisors is an integer number (177001015611).

Almost surely, 2354002031221 is an apocalyptic number.

It is an amenable number.

354002031221 is a deficient number, since it is larger than the sum of its proper divisors (1).

354002031221 is an equidigital number, since it uses as much as digits as its factorization.

354002031221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 354002031221 its reverse (122130200453), we get a palindrome (476132231674).

The spelling of 354002031221 in words is "three hundred fifty-four billion, two million, thirty-one thousand, two hundred twenty-one".