3540031541 has 2 divisors, whose sum is σ = 3540031542. Its totient is φ = 3540031540.

The previous prime is 3540031511. The next prime is 3540031543. The reversal of 3540031541 is 1451300453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3537751441 + 2280100 = 59479^2 + 1510^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3540031541 is a prime.

It is a super-2 number, since 2×3540031541² = 25063646622549669362, which contains 22 as substring.

Together with 3540031543, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3540031541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3540031543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1770015770 + 1770015771.

It is an arithmetic number, because the mean of its divisors is an integer number (1770015771).

Almost surely, 2^3540031541 is an apocalyptic number.

It is an amenable number.

3540031541 is a deficient number, since it is larger than the sum of its proper divisors (1).

3540031541 is an equidigital number, since it uses as much as digits as its factorization.

3540031541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 26.

The square root of 3540031541 is about 59498.1641817628. The cubic root of 3540031541 is about 1524.0610959460.

Adding to 3540031541 its reverse (1451300453), we get a palindrome (4991331994).

The spelling of 3540031541 in words is "three billion, five hundred forty million, thirty-one thousand, five hundred forty-one".