354040133411 has 2 divisors, whose sum is σ = 354040133412. Its totient is φ = 354040133410.

The previous prime is 354040133399. The next prime is 354040133413. The reversal of 354040133411 is 114331040453.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 354040133411 - 2⁶ = 354040133347 is a prime.

It is a super-4 number, since 4×354040133411⁴ (a number of 47 digits) contains 4444 as substring.

Together with 354040133413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (354040133413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177020066705 + 177020066706.

It is an arithmetic number, because the mean of its divisors is an integer number (177020066706).

Almost surely, 2^354040133411 is an apocalyptic number.

354040133411 is a deficient number, since it is larger than the sum of its proper divisors (1).

354040133411 is an equidigital number, since it uses as much as digits as its factorization.

354040133411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 354040133411 its reverse (114331040453), we get a palindrome (468371173864).

The spelling of 354040133411 in words is "three hundred fifty-four billion, forty million, one hundred thirty-three thousand, four hundred eleven".