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35424049961 is a prime number
BaseRepresentation
bin100000111111011100…
…000001101100101001
310101102202121012010102
4200333130001230221
51040022024044321
624135032155145
72362561312406
oct407734015451
9111382535112
1035424049961
1114028a53053
126a47538ab5
133457035c11
141a009712ad
15dc4de4c0b
hex83f701b29

35424049961 has 2 divisors, whose sum is σ = 35424049962. Its totient is φ = 35424049960.

The previous prime is 35424049957. The next prime is 35424049963. The reversal of 35424049961 is 16994042453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31335726361 + 4088323600 = 177019^2 + 63940^2 .

It is a cyclic number.

It is not a de Polignac number, because 35424049961 - 22 = 35424049957 is a prime.

It is a super-3 number, since 3×354240499613 (a number of 33 digits) contains 333 as substring.

It is a Sophie Germain prime.

Together with 35424049963, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (35424049963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17712024980 + 17712024981.

It is an arithmetic number, because the mean of its divisors is an integer number (17712024981).

Almost surely, 235424049961 is an apocalyptic number.

It is an amenable number.

35424049961 is a deficient number, since it is larger than the sum of its proper divisors (1).

35424049961 is an equidigital number, since it uses as much as digits as its factorization.

35424049961 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 933120, while the sum is 47.

The spelling of 35424049961 in words is "thirty-five billion, four hundred twenty-four million, forty-nine thousand, nine hundred sixty-one".