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354342771149 is a prime number
BaseRepresentation
bin1010010100000000111…
…10011001100111001101
31020212121202102211102212
411022000132121213031
521301143222134044
6430441031200205
734412641600433
oct5120036314715
91225552384385
10354342771149
11127304290614
1258810816065
1327550514ab3
1413216530d53
15933d435a9e
hex52807999cd

354342771149 has 2 divisors, whose sum is σ = 354342771150. Its totient is φ = 354342771148.

The previous prime is 354342771119. The next prime is 354342771151. The reversal of 354342771149 is 941177243453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 329111037124 + 25231734025 = 573682^2 + 158845^2 .

It is a cyclic number.

It is not a de Polignac number, because 354342771149 - 28 = 354342770893 is a prime.

Together with 354342771151, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 354342771097 and 354342771106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354342771119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177171385574 + 177171385575.

It is an arithmetic number, because the mean of its divisors is an integer number (177171385575).

Almost surely, 2354342771149 is an apocalyptic number.

It is an amenable number.

354342771149 is a deficient number, since it is larger than the sum of its proper divisors (1).

354342771149 is an equidigital number, since it uses as much as digits as its factorization.

354342771149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2540160, while the sum is 50.

The spelling of 354342771149 in words is "three hundred fifty-four billion, three hundred forty-two million, seven hundred seventy-one thousand, one hundred forty-nine".